数据库中表数据，如下图：

实现的需求是，如果suporgcode数据为null 的情况下，表示在一级节点 "请选择" 的二级节点，然后是如：3和36 是1的子节点，一步一步的节点延伸

java代码拼接方式如下：

/** 
 * 拼接成json类型  事故类型   
 * @author X-rapido 
 */  
public String createJSONData(String instcode){  
    // 查询一级节点  
    String sql="select orgcode,orgname,suporgcode from swe_emerplanorg where instcode='"+instcode+"' and suporgcode is null order by orgcode";  
    List list=jdbcT.queryForList(sql);  
    StringBuffer json=new StringBuffer("[{\"id\":\"0\",\"text\":\"请选择\",\"children\":[");   // 初始化根节点  
    if(list!=null && list.size()>0){  
        for(int i=0; i<list.size();i++){  
            Map v_map = (Map)list.get(i);  
        json.append(this.getChildren(instcode,v_map.get("ORGCODE").toString()));    // 获取子节点  
        }  
        json=new StringBuffer(json.substring(0, json.length()-1)+"]}]");  
    }  
    System.out.println(json);  
    return json.toString();  
}  
/** 
 * 得到子节点 
 */  
private String getChildren(String instcode,String orgcode){  
String sql = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and orgcode='"+orgcode+"' and suporgcode is null order by orgcode";  
    List list=jdbcT.queryForList(sql);  
    StringBuffer child_json=new StringBuffer();  
    if(list!=null && list.size()>0){  
        for(int i=0; i<list.size();i++){  
            Map v_map = (Map)list.get(i);  
            child_json.append("{\"id\":\""+v_map.get("ORGCODE").toString().trim()+"\",");  
            child_json.append("\"text\":\""+v_map.get("ORGNAME").toString().trim()+"\"");  
            String sql_2 = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and suporgcode='"+v_map.get("ORGCODE")+"' order by orgcode";  
            List t_l=jdbcT.queryForList(sql_2);  
            if(t_l!=null && t_l.size()>0){  
                child_json.append(",\"children\":[");  
                for(int t=0; t<t_l.size();t++){  
                    Map t_m = (Map)t_l.get(t);  
                    child_json.append("{\"id\":\""+t_m.get("ORGCODE").toString().trim()+"\",");  
                    child_json.append("\"text\":\""+t_m.get("ORGNAME").toString().trim()+"\"");  
                    child_json.append(getNodes(instcode,t_m.get("ORGCODE").toString()));    // 下级节点  
                }  
                child_json=new StringBuffer(child_json.substring(0, child_json.lastIndexOf(","))+"]},");  
            }else{  
                child_json.append("},");  
            }  
        }  
    }else{  
        child_json.append("},");  
    }  
    return child_json.toString();  
}  
  
/** 
 * 获得节点  
 */  
public String getNodes(String instcode,String orgcode){  
String sql = "select orgcode,orgname,suporgcode from swe_emerplanorg where instcode ='"+instcode+"' and suporgcode ='"+orgcode+"' order by orgcode";  
    List list=jdbcT.queryForList(sql);  
    StringBuffer j_s=new StringBuffer();  
    if(list!=null && list.size()>0){  
        j_s.append(",\"children\":[");  
        for(int i=0; i<list.size();i++){  
            Map t_m = (Map)list.get(i);  
            j_s.append("{\"id\":\""+t_m.get("ORGCODE").toString().trim()+"\",");  
            j_s.append("\"text\":\""+t_m.get("ORGNAME").toString().trim()+"\"");  
            j_s.append(getNodes(instcode,t_m.get("ORGCODE").toString()));  
        }  
    }else{  
        j_s.append("},");  
    }  
    if(j_s.toString().contains("children")){  
        j_s=new StringBuffer(j_s.substring(0, j_s.lastIndexOf(",")));  
        j_s.append("]},");  
    }  
    return j_s.toString();  
}

最终的实现图如下

未经允许请勿转载：程序喵 » jQuery UI Tree组件的json格式，java递归拼接demo